Friday, October 10, 2014

Algebra - Part 7 - Elimination Method

Elimination Method
2a + b = 13 ……..(1)
3a + 2b = 21…… (2)

Decide which variable you want to eliminate.
Let us eliminate the variable  ‘b’.

Look at the number before ‘b’.
1 and 2.

We have to make these two numbers equal.


Let us multiply (1) by 2.

(1) x 2     4a + 2b = 26…….(3)
(2)          3a + 2b = 21…… (2)

Now we made the numbers equal. (2, 2)

Look at the sign of the two numbers.  (+2 , +2)
If they are of the same sign (+,+) or (,) to eliminate ‘b’, we need to subtract the equations.
If they are of different sign, (+,), we need to add the equations.


Since both numbers are of the same sign, we subtract.
4a + 2b = 26 ……(3)
3a + 2b = 21 ……(2)

(3) – (2),
(4a + 2b) – (3a + 2b) = 26 21
4a + 2b 3a 2b = 26 – 21
                            a = 5

Substitute a = 5 in (1),
(1)  2a + b = 13
          2(5) + b = 13
            10 + b = 13
                     b = 13 – 10
                     b = 3