Apply what you have learnt in this
series of lessons and solve the following problem:
A person drives from Town A to Town B, a
distance of 240 km.
While
returning from town B, due to heavy traffic,
his speed was reduced by 20 km/h and the return journey took 1 hour more than
his onward journey.
Form a quadratic equation and find his
onward speed from Town A to town B.
Onward Journey from Town A to Town
B
Let his speed = x km/h.
Time = distance/speed
= 240/x hours.
Return Journey from Town B to Town A
His speed was reduced by 20km/h due to heavy
traffic.
So speed = (x – 20) km/h.
Time = 240/(x – 20) hours.
Solve to find x:
(x – 80) (x + 60) = 0
(x – 80)= 0 or (x + 60) = 0
x = 80 or x = – 60
(rejected)
His onward
speed from Town A to town B is 80 km/h.
